verify that 3 and -2 are the zeros of quadratic polynomial p(x) = x²-x-6 and verify the relationship between the zeros and the coefficient
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Answer:
Step-by-step explanation:
Let,
P(3)=3
2
−3−6=9−9=0
P(−2)=(−2)
2
−(−2)−6
=4+2−6=0
P(3)=0 and P(−2)=0
∴3 and −2 are the zeroes of the polynomials
x²−x−6
sum of zeroes (α+β)= 3+(-2)=3-2=1
=1/1=coef.of x/coeff.of x²
product of zeroes (αβ)= (3)(-2)=-6 = 6/1 =conatant term / coffi.of x²
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