verify that -3 and 5 are the zero of the polynomial q(x)=(x+3) (x-5)
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Answer:
put eq = 0
Step-by-step explanation:
q(x) = 0
(x+3)(x-5)=0
x+3 = 0/(x-5)
x+3 = 0
x= -3
Thus, it is a zero of the polynomial
Also,
x-5=0/(x+3)
x-5 = 0
x = 5
Hence, it is a zero of the polynomial
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