Verify that -3 is a zero of p(x) = x2+x-6
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Answered by
1
Answer:
gievn,
p(x ) = x² +x -6 = p
so,
p(-3) = (-3)² + (-3) - 6
= 9 -3 -6
= 0
so,
-3 is a zero of p(x)
Answered by
0
Answer:
-3 is a zero of p(x).
Step-by-step explanation:
p(x) =x*2+x-6
p(-3)= (-3)*2+(-3)-6
= 9 -3 -6
= 9 -9
= 0
please mark as brain list.
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