Math, asked by harshsingh77, 11 months ago

verify that (5A)' = 5A'​

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Answered by BrainlyWarrior
70

Here A = \left[\begin{array}{c c c} 3&2&4 \ \\ 2&1&1 \\ 1&3&5 \end{array} \right]

L.H.S : ( 5A )' :

( 5A ) = 5 \left[\begin{array}{c c c} 3&2&4 \ \\ 2&1&1 \\ 1&3&5 \end{array} \right] = \left[\begin{array}{c c c} 15&10&20 \ \\ 10&5&5 \\ 5&15&25\end{array} \right]

Now ( 5A )' = \left[\begin{array}{c c c} 15&10&5 \ \\ 10&5&15 \\ 20&5&25\end{array} \right]

R.H.S : 5A' : A' = \left[\begin{array}{c c c} 3&2&1 \ \\ 2&1&3 \\ 4&1&5 \end{array} \right]

Now 5A' = 5 \left[\begin{array}{c c c} 3&2&1 \ \\ 2&1&3 \\ 4&1&5 \end{array} \right] = \left[\begin{array}{c c c} 15&10&5\ \\ 10&5&15 \\ 20&5&25\end{array} \right]

L.H.S = R.H.S

Hence Proved.

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