Question

verify that -(a+b)=(-a)+(-b) where a = -3/4 and b =-6/7​

Answer 1

Answer:

Step 1: Draw a square and cut into 3 parts.

Step 2: There are 1 hided square green and 2 rectangles (pink, blue)

Step 3: Area of the full square = a

2

−b

2

Step 4: Now we have to find the area of rectangle as shown in the figure.

Step 5: Consider the area of pink rectangle = length × breadth = a(a−b)

Step 6: Area of blue rectangle = b(a−b)

Step 7: Area of full square = area of pink rectangle + area of blue rectangle.

i.e., a

2

−b

2

=a(a−b)+b(a−b)

a

2

−b

2

=(a+b)(a−b)

Hence, geometrically we proved the identity a

2

−b

2

=(a+b)(a−b).

Answer 2

Answer:

$- (a + b) = ( - a) + ( - b)$

$- ( \frac{ - 3}{4} - \frac{6}{7}) = \frac{3}{4} + \frac{6}{7}$

$- ( \frac{ - 21 - 24}{28} ) = \frac{21 + 24}{28}$

$- ( - \frac{45}{28} ) = \frac{45}{28}$

$\frac{45}{28} = \frac{45}{28}$

hence proved.

Step-by-step explanation:

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