Verify that a÷(b+c)≠(a÷b)+(a÷c) for each of the following values of a,b,c.
A. a=(12), b=3, c=-1
B. a=6, b.=(-2), c=1.
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Given : a÷(b+c)≠(a÷b)+(a÷c)
To Find : Verify for each of the following values of a,b,c.
A. a=(12), b=3, c=-1
B. a=6, b.=(-2), c=1.
Solution:
a÷(b+c)≠(a÷b)+(a÷c)
A. a=(12), b=3, c=-1
LHS = a÷(b+c)
= 12 ÷(3-1)
= 12 ÷ 2
= 6
RHS = (a÷b)+(a÷c)
= (12÷3)+(12÷(-1))
= 4 - 12
= - 8
6 ≠ - 8
Verified that
a÷(b+c)≠(a÷b)+(a÷c)
B. a=6, b=-2 c= 1
LHS = a÷(b+c)
= 6 ÷(-2+1)
= 6 ÷ (-1)
= -6
RHS = (a÷b)+(a÷c)
= (6÷(-2))+(6÷( 1))
= -3 +6
= 3
-6 ≠ 3
Verified that
a÷(b+c)≠(a÷b)+(a÷c)
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