Question

Verify that a÷(b+c) = (a÷b) +(a÷c) for each of the following values of a, b and c where a =12 ,b = -4 , C = 2.

Answer 1

a÷(b+c) = (a÷b) +(a÷c)

a/(b+c) = a/b + a/c

12/-2 = 12/-4 + 12/2

-6 = -3 +6

-6 = 3

here LHS is not equal to RHS

hence this equation is wrong

Answer 2

Question

Verify that a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) for each of the following values of a,b and c. a = 12,b = 4,c = 2.

Given

• a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

a = 12,b = 4,c = 2.

${ \underline{\large{ \bf{Putting \: the \: given \: values \: in \: L.H.S}}}}$

$\dashrightarrow{ \sf{ = 12 \div ( - 4 + 2)}} \\ \\ \dashrightarrow{ \sf{ = 12 \div ( - 2) = 12 \div}} { \huge{[}} { \sf{ \dfrac{ - 1}{2}}} { \huge{]}}$ $\sf{ = \dfrac{ - 12}{2} = - 6}$

${ \underline{\large{ \bf{Putting \: the \: given \: values \: in \: R.H.S}}}}$

$\dashrightarrow \sf{[12 \div ( - 4)] + (12 \div 2)}$

$\sf{ = { \huge{(}} \sf{12 \times \dfrac{ - 1}{4}{ \huge{)}}}} \sf{ \div 6 = 3 + 6 = 3}$

$\mathcal{Since,}$ L.H.S ≠ R.H.S.

${ \underline{\bf{Hence \: Verified}}}$