verify that a÷(b+c) = (a÷b) +(a÷c) for (i) a=-10,b=1 and c=1 (ii) a=12,b=1, and c=-2
Answers
Answer: We have verified that a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
for each of the following values of a, b and c.
(a) a = 12, b = – 4, c = 2 (b) a = (–10), b = 1, c = 1.
Step-by-step explanation:
a=-10,b=1 and c=1 (ii) a=12,b=1, and c=-2
We will be using the concept of the division of integers to solve the given questions.
To check: a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) ------------- (1)
a) a =-10, b = 1, c = 1
Take L.H.S, a ÷ (b + c)
Putting the values of a, b and c, we get
= a ÷ (b + c)
= -10 ÷ (1 + 1)
= -10 ÷ (2)
= -5
Now take R.H.S, (a ÷ b) + (a ÷ c)
= [-10 ÷ 1] + (-10 ÷ 1)
= [-10 ] + (-10)
= -10-10
= -20
Putting the values of L.H.S and R.H.S in equation (1), we get
a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
-5 ≠ -20
L.H.S ≠ R.H.S
Hence verified
b) a = 12, b = 1, c = -2
Take L.H.S, a ÷ (b + c)
Putting the values of a, b and c, we get
= a ÷ (b + c)
= 12 ÷ (1 + -2)
= 12 ÷ (1)
= 12
Now take R.H.S, (a ÷ b) + (a ÷ c)
= [12 ÷ 1] + (12 ÷ -2)
= (12) + (-6)
=6
Putting the values of L.H.S and R.H.S in equation (1), we get
a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
12 ≠ 6
L.H.S ≠ R.H.S
Hence verified