Verify that a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) when a = 3, b = – 5, c = 7.
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Answered by
1
Step-by-step explanation:
a=3,b=-5,c=7 thn
a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) take whole equation as LHS and RHS
thn a ÷ (b + c) will be LHS and (a ÷ b) + (a ÷ c) will be RHS
first take LHS a ÷ (b + c) it means 3/(-5+7) do first bracket (-5+7=2) and thn devide by 3=3/2=-1.2.
now take RHS (a ÷ b) + (a ÷ c) means
(3/-5)+(3/7)=-0.17142.
it means LHS is not equal to RHS
Answered by
3
Answer :D
Given: a = 3 b = -5 c = 7
So,
Take a ÷ (b + c) as LHS
and (a ÷ b) + (a ÷ c) as RHS
putting the given values
LHS = 3 ÷ (-5 + 7)
LHS = 3 ÷ 2 = 1.5
Now,
RHS = (3 ÷ (-5)) + (3 ÷ 7)
RHS = −0.2714285714285714285
LHS ≠ RHS
Hence Verified
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