Question

Verify that (a+b)+c = a+(b+c), a= -12,b= -9/11,c= 7/-12​

Answer 1

[a+b]+c=a+[b+c]

[-12-9]+7/-12=-12[-9+7/12]

[-21]+7/-12=-12[108+7/-12]

252+7/-12=144+115/-12

259/-12=259/-12

Answer 2

Answer:

(a+b)+c = a+(b+c)

Step-by-step explanation:

Given: a= -12,

b= -9/11,

c= 7/-12

To Prove: (a+b)+c = a+(b+c)

Proof:

Here,

(a+b)+c

{(-12) + (-9/11)} + (- 7/12)

{(-12) - 9/11} - 7/12

(-12 - 9/11) - 7/12

(- 12 * 11 - 9/11) - 7/12

(- 132 -9/11) - 7/12

(- 141/11) - 7/12

- 141/11 - 7/12

- 141 * 12 - 7 * 11/11 * 12

-1692 - 77/132

- 1769/132

Now,

a+(b+c)

(- 12) + {(- 9/11) + (- 7/12)}

(- 12) + (- 9/11 - 7/12)

(- 12) - 9/11 - 7/12)

(- 12) - 9 * 12 - 7 * 11/11 * 12

(- 12) - 108 - 77/132

(- 12) - 185/132

- 12 - 185/132

(- 12) * (132) - 185/132

- 1584 - 185/132

- 1769/132

here,

(a+b)+c = (- 1769/132)

a+(b+c) = (- 1769/132)

So,

(a+b)+c = a+(b+c)

HENCE VERIFIED