Question

Verify that (a+b)+c = a+(b+c), a= -12,b= -9/11,c= 7/-12​

Answer 1

a(a+b)+c = a+(b+c), a= -12,b= -9/11,c= 7/-12

Answer 2

$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Question}}}}}{\bigstar}$

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Verify that (a+b)+c = a+(b+c), a= -12, b=$\displaystyle\frac{ -9}{11}$ , c= $\displaystyle\frac{7}{-12}$

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$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Answer}}}}}{\bigstar}$

$\boxed{\red{\bold{Solving \ a+(b+c):}}}$

$\red{\implies}-12 + \displaystyle\left( \frac{-9}{11} +\frac{7}{-12}\right)$

$\red{\implies}-12 + \displaystyle \left( \frac{-9}{11} - \frac{7}{12}\right)$

$\red{\implies}-12 + \displaystyle \left( \frac{-108 - 77}{132}\right)$

$\red{\implies}-12 + \displaystyle \frac{-185}{132}$

$\red{\implies}-12 - \displaystyle\frac{185}{132}$

$\red{\implies}\displaystyle\frac{-1584 - 185}{132}$

$\red{\implies}\displaystyle\frac{-1769}{132}$

$\boxed{\red{\bold{Solving\ for \ (a+b)+c:}}}$

$\blue{\implies}\displaystyle \left( -12 + \frac{-9}{11} \right) + \frac{7}{-12}$

$\blue{\implies}\displaystyle \left( -12 - \frac{9}{11} \right) - \frac{7}{12}$

$\blue{\implies}\displaystyle \left( \frac{-132 - 9}{11} \right) - \frac{7}{12}$

$\blue{\implies}\displaystyle \frac{-141}{11} - \frac{7}{12}$

$\blue{\implies}\displaystyle \frac{-1692- 77}{132}$

$\blue{\implies}\displaystyle \frac{-1769}{132}$

$\green{\boxed{\implies{\boxed{Hence \ a+(b+c) = (a+b)+c}}}}$

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