Question

Verify that (a + b) + c = a + (b + c) by taking​

Answer 1

Answer:

hope it will be helpful for you

Answer 2

$\sf\blue{\underline{✯ Given :-}}$

• $\tt {a} = \frac{-9}{11}$
• $\tt {b} = \frac{3}{-5}$
• $\tt {c} = \frac{-9}{22}$

$\sf\pink{\underline{✯To \: find :-}}$

• Verification of the equation :-

(a + b) + c = a + (b + c)

$\sf\orange{\underline{✯ Solution :-}}$

• Taking the equation (a + b) + c as R.H.S and the equation a + (b + c) as L.H.S

Now,

$\sf\bold\green{\underline{✯ Calculation \: for \: the \: first \: equation :-}}$

$\tt \:{ \underline{ \boxed { \blue{a + (b + c)}}}} \\ \tt = \frac{ - 9}{11} + ( \frac{ - 3}{ 5} + \frac{ - 9}{22} ) \\ \tt \: = \frac{ - 9}{11} + ( \frac{ - 66 + ( - 45)}{110} ) \\ \tt = \frac{ - 9}{11} + ( \frac{ - 66 - 45}{110} ) \\ \tt = \frac{ - 9}{11} + \frac{ - 111}{110} \\ \tt = \frac{ - 90 + ( - 111)}{110} \\ \tt = \frac{ - 90 - 111}{110} \\ \tt = { \blue \bigstar{ \underline{ \boxed{\frac{ - 201}{110}}}}}{ \blue \bigstar}$

$\sf\bold\green{\underline{✯ Calculation \: for \: the \: second \: equation :-}}$

$\tt { \underline{ \boxed{ \orange{(a + b) + c}}}} \\ \tt \: = ( \frac{ - 9}{11} + \frac{ - 3}{5} ) + \frac{ - 9}{22} \\ \tt = {\frac{ - 45+ ( - 33)}{55}} + \frac{ - 9}{22} \\ \tt = \frac{ - 45 - 33}{55} + \frac{ - 9}{22} \\ \tt = \frac{ - 78}{55} + \frac{ - 9}{22} \\ \tt = \frac{ - 156 + ( - 45)}{110} \\ \tt = \frac{ - 156 - 45}{110} \\ { \orange \bigstar{ \underline{ \boxed{ \tt = \frac{- 201}{110} }}}}{ \orange \bigstar}$

• As observation we have solved the both equation and got the same results i.e., $\sf {\bold{ \frac{-201}{110}}}$

$\bf{\underline{\boxed{\therefore \bf L.H.S = R.H.S}}}$

$\mathfrak { \underline{\boxed{ \green{ \sf ✧Hence, \purple V \red e \orange r \pink f \blue i \green e \blue d: -}}}}$