Question

verify that (a+b)+c=a+(b+c) where a=-1/2,b=3/4,c=5/7​

Answer 1

Step-by-step explanation:

$(a + b) + c = a + (b + c) \\ \\ ( - \frac{1}{2} + \frac{3}{4} ) + \frac{5}{7} = - \frac{1}{2} + ( \frac{3}{4} + \frac{5}{7} ) \\ \\ (\frac{ - 2 + 3}{4} ) + \frac{5}{7} = - \frac{1}{2} + ( \frac{21 + 20}{28} ) \\ \\ \frac{1}{4} + \frac{5}{7} = - \frac{1}{2} + \frac{41}{28} \\ \\ \frac{7 + 20}{28} = \frac{ - 14 + 41}{28} \\ \\ \frac{27}{28} = \frac{27}{28}$

LHS = RHS

Proved.

Answer 2

Answer:

L.H.S

(a+b)+c

=(-1/2+3/4)+5/7

=(-2+3/4)+5/7

=1/4+5/7

=7+20/28

=27/28

R.H.S

a+(b+c)

=-1/2+(3/4+5/7)

=-1/2+(21+20/28)

=-1/2+41/28

=-14+41/28

=27/28

therefore, L.H.S=R.H.S

Hence verified