Verify that at a÷(b+c) not equal to (a÷b)+(a÷c)
a=2, b=3 c= -2
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Answered by
0
Answer:
given a= 2, b=3, c=-2
to proof : a÷ (b+c) not equal to (a÷b) + (a÷c)
solution: LHS= 2÷(3+(-2))
LHS=2÷(3-2)
LHS=2÷1=2
taking RHS= 2÷3+2÷ -2= -1/3
hence LHS is not equal to RHS
hence proved
hope it helps u
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Answered by
3
Given:
- a = 2
- b = 3
- c = -2
Need to verify:
- a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
Substitute the values:
⟹ 2 ÷ {3 + (-2)} ≟ (2 ÷ 3) + {(2 ÷ (-2)}
⟹ 2 ÷ ( 3 - 2 ) ≟ (2/3) + ( - 1 )
⟹ 2 ÷ ( 1 ) ≟ ( 2/3 ) - 1
⟹ 2/1 ≟ (2/3) - (3/3)
⟹ 2 ≟ -1/3
⟹ 2 ≠ -1/3
LHS ≠ RHS, so they are not equal.
Hence verified.
More:
Distributive property:
For numbers a, b and c ( where a, b and c are real numbers )
a( b + c ) = a×b + a×c
a( b - c ) = a×b - a×c
But this thing isn't true if we replace multiplication by division i.e.
a÷( b + c ) ≠ a ÷ b + a ÷ c
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