Verify that for two sets A and B, n(A x B) =pq, where n(A) = p and n(B)= q. the total
number of relations from A to B is 2^pq
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Answer:
Taking left hand side ,we get_
n(A×B)
by using distributive identity (a(b+c) =A×B +A×C)
n×A +n×B
by putting values of n(a) and n(b) in the equation ,we get_
p×q
=pq
Here, pq =pq
LHS = RHS
Hence, verified.
Step-by-step explanation:
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