Question

Verify that HCF a,b, c ×LCM a,b,c is not equal to a×b×c by taking a=63 b=36 c =108

Answer 1

Step-by-step explanation:

I think that the product of 2 numbers is equal to product of their HCF and LCM.

Answer 2

Given:

a=63

b=36

c =108

To verify:

HCF a,b,c × LCM a,b,c ≠ a×b×c

Solution:

We have given three 63, 36, and 108

We will find the prime factorization of the given numbers

• 63 = 3 × 3 × 7
• 36 = 2 × 2 × 3 × 3
• 108 = 2 × 2 × 3 × 3 × 3

LCM [63, 36, 108] = 2×2×3×3×3×7 = 756

HCF [63, 36, 108] = 3×3 = 9

• LCM [63, 36, 108]×HCF [63, 36, 108] = 756×9 = 6804

So,

the products of the numbers is given by;

• 63×36×108 = 244944

hence

HCF a,b,c × LCM a,b,c ≠ a×b×c