Question

verify that points P(-2, 2), Q(2, 2) and R(2, 7) are vertices of a right angled
triangle
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Answer 1

Answer:

Step-by-step explanation:

PQ = 4

QR = 5

PR = $\sqrt{41}$

$PQ^2 +QR^2 = 16 + 25 = 41 \\PR^2 = 41$

∴ $PQ^2 +QR^2 =PR^2$

Answer 2

Answer:

In an X Y axis we plot PQand R.

Step-by-step explanation:

RQ IS VERTICAL and is 7-2 = 5.

PQ is horizontal and is 2- (-2) = 4

Note RQ is perpendicular to PQ just as the Y axis is perpendicular to the X axis.

HencePQR is right angled triangle.