Verify that : sin2A=2tanA/1+tan?A Given: A =30
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sin2A=sin(2×30°)=sin60°=√3/2
2tanA/1+tan²A
=2tan30°/1+tan²30°
={2×(1/√3)}/{1+(1/√3)²}
=(2/√3)/(1+1/3)
=(2/√3)/(4/3)
=2/√3×3/4
=√3/2
∴, LHS=RHS (Proved)
2tanA/1+tan²A
=2tan30°/1+tan²30°
={2×(1/√3)}/{1+(1/√3)²}
=(2/√3)/(1+1/3)
=(2/√3)/(4/3)
=2/√3×3/4
=√3/2
∴, LHS=RHS (Proved)
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