verify that the following system of equations is consistent: x + 2y +2z = 1, 2x + y + z = -2, 3x + 2y + 2z =3, y + z = 0.
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Answer:
No solution.
Step-by-step explanation:
x+2y+2z= 1,2x+y+z=-2,3x+2y+2z=3, y+z=0
Isolate y for y + z =0: y=-z
{Substitute} y=-z
x+2 (-z)+2z=1
2x-z+z=- 2
3x+2(-z)+2z=3
Simplify:
x=1
2x=-2
3x=3
{Substitute} x=1
2·1=-2
3=3
Simplify:
2=-2
3=3
No solution.
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