Verify that the numbers given along side of the cubic polynomial below are their zeros.Also verify the relationship between the zeros and coefficients in each case: (i) f(x)=2x^(3)+x^(2)-5x+2;
(1)/(2) , 1 , -2
Answers
Answered by
2
f(x) =2x^3+x^2-5x+2
f(1/2)=2(1/2)^3+(1/2)^2-5(1/2)+2
f(1/2)=2(1/8)+1/4-5/2+2
f(1/2)=1/4+1/4-5/2+2
f(1/2)=2/4-5/2+2
f(1/2)=(1×2)-(2×5)/4+2
f(1/2)=2-10/4+2
f(1/2)=-8/4+2
f(1/2)=-2+2
f(1/2)=0
f(1)=2(1)^3+(1)^2-5(1)+2
f(1)=2(1)+1-5(1)+2
f(1)=2+1-5+2
f(1)=3-5+2
f(1)=-2+2
f(1)=0
f(-2)=2(-2)^3+(-2)^2-5(-2)+2
f(-2)=2(-8)+4+10+2
f(-2)=-16+4+10+2
f(-2)=-12+10+2
f(-2)=-2+2
f(-2)=0
(1)/(2) , 1 , -2 are the zeroes of the cubic polynomial f(x)=2x^(3)+x^(2)-5x+2
Relationship between zeroes and coefficients
Sum of zeroes=-(coefficient of x^2)/coefficient of x^3=-1/2
Product of zeroes=-(constant term) /coefficient of x^3=-2/2=-1
Sum and product of zeroes taken at a time
=Coefficient of x/coefficient of x^3=-5/2
I hope it's help you
Plz mark my answer as a brainliest answer
Similar questions