Verify that x=3 is a zero of the polynomial
p(x)=2x3
-5x2
-4x+3.
Answers
Answered by
43
Hiii friend,
X = 3
P(X) = 2X³-5X²-4X+3
P(3) = 2 × (3)³ - 5 × (3)² - 4 × 3 +3
=> 2 × 27 - 5 × 9 -12 +3
=> 54 -45 - 12 +3
=> 57 -57
=> 0
Remainder is 0 hence 3 is a zero of the given polynomial.
HOPE IT WILL HELP YOU...... :-)
X = 3
P(X) = 2X³-5X²-4X+3
P(3) = 2 × (3)³ - 5 × (3)² - 4 × 3 +3
=> 2 × 27 - 5 × 9 -12 +3
=> 54 -45 - 12 +3
=> 57 -57
=> 0
Remainder is 0 hence 3 is a zero of the given polynomial.
HOPE IT WILL HELP YOU...... :-)
Answered by
23
hii friend
here's ur answer hope it helps uuu...
x=3
so now we will fill the value of x in our given polynomial...
we can take the polynomial as
P(x)
so, p(x)=2x^3 -5x^2 - 4x +3
2(3)^3 - 5(3)^2 - 4×3 + 3
2×27 - 5× 9 -12+3
54-45-12+3
57-57
0
hence ,proved
here's ur answer hope it helps uuu...
x=3
so now we will fill the value of x in our given polynomial...
we can take the polynomial as
P(x)
so, p(x)=2x^3 -5x^2 - 4x +3
2(3)^3 - 5(3)^2 - 4×3 + 3
2×27 - 5× 9 -12+3
54-45-12+3
57-57
0
hence ,proved
Anonymous:
hii saniya
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