verify that x^3+y^3+z^3-3xyz=1/2(x+y+z){(x-y)^2+(y-z)^2+(z-x)^2}
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Answer:
3^x+3^y
=6^x(^y)z^3-3
=0
1/2(x+y+z)
1/2xyz
am I right
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