Question

verify that (x-y)-1 not equal to x-1-y-1 by taking x=-2/7, y=4/7​

Answer 1

Answer:

Answer is at above photo

Answer 2

Numbers

Given that $x=\frac{-2}{7} \ and \ y=\frac{4}{7}$

By substituting  these values, it is needed to verify,

$(x-y)-1\neq x-1-y-1$

on solving L.H.S. we get,

$\implies (\frac{-2}{7}-\frac{4}{7})-1$

$=\frac{-6}{7} -1=\frac{-13}{7}$

on solving R.H.S. we get,

$\frac{-2}{7}-1- \frac{4}{7}-1\\ \\=\frac{-20}{7}$

Hence,

$\frac{-13}{7}\neq \frac{-20}{7}$

Therefore, verified.