Question

verify that (x×y)^-1 = x^-1 × y^-1 when x = -2/3 and y = -3/5

Answer 1

Answer:

x=-2/3 and y=-3/5 (-2/3×-3/5)-/^-1 = -2/3^-1×-3/5^-1. (-2/5)^-1 =(-2/5)^-1.

2/5=2/5.

LHS=RHS.

hope I help u

Answer 2

Answer:

The value of (x $*$ y)⁻¹ = x⁻¹ $*$ y ⁻¹ is 5/2.

Step-by-step explanation:

Given:  

(x $*$ y)⁻¹ = x⁻¹ $*$ y ⁻¹  then x = -2/3 and y = -3/5

To find:  

the value of LHS = RHS

Step 1

Let (x $*$ y)⁻¹ = x⁻¹ $*$ y ⁻¹

x = -2/3 and y = -3/5

Substitute the values of x and y, then we get

LHS = (x $*$ y)⁻¹

= ( (-2/3) $*$ (-3/5) ) ⁻¹

= ( 2/5) ⁻¹

= 5/2

(x $*$ y)⁻¹ = 5/2

Step 2

Let (x $*$ y)⁻¹ = x⁻¹ $*$ y ⁻¹

x = -2/3 and y = -3/5

Substitute the values of x and y, then we get

RHS = x⁻¹ $*$ y ⁻¹

= (-2/3)⁻¹ $*$ (-3/5)⁻¹

= (-3/2) $*$ (-5/3)

= 5/2

x⁻¹ $*$ y ⁻¹ = 5/2

LHS = RHS

Therefore, the value of (x $*$ y)⁻¹ = x⁻¹ $*$ y ⁻¹ is 5/2.

#SPJ2