verify that |x+y|≤|x|+|y| by taking x=2/3, y=-3/5
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Answered by
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Answer:
2/3 +3/5 greater than (2/3) + (3/5)
LHS RHS
2/3 ×5=10/5 2/3×5=10 /5
3/5×3=9/15 3/5×3=9/15
=10/15 +9/15 =10/15 +9/15 = 19/15 =19/15
19/15 =19/15
therefore it is not greater than
Answered by
24
Answer:|x+y| < |x| + |y|
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