verify the a (b + c) ≠ [a÷b] + [a÷c] for
a=-10,b = 1 and C=1
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Given:- a=-10
b=1
c=1
Solution:- a÷(b+c)≠(a÷b)+(a÷c)
L.H.S. -10÷(1+1)
= -10÷2
= -5
R.H.S. (a÷b)+(a÷c)
= (-10÷1)+(-10÷1)
=-10+(-10)
=-10-10
=-20
L.H.S.≠R.H.S.
a÷(b+c)≠(a÷b)+(a÷c)
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