Question

verify the algebraic identity (a+b)^2=a^2+b^2-2ab.​

Answer 1

LHS =RHS

LHS

$(a + b)^{2}$

$(a + b)(a + b)$

$a(a + b) + b(a + b)$

$a ^{2} + ab + ab + b ^{2}$

$a ^{2} + 2ab + b ^{2}$

RHS

$a ^{2} + 2ab + b ^{2}$

So,LHS =RHS

Answer 2

Answer:

(a + b)^2= (a +b)(a+b)

= a×(a + b) + b×(a+b)

=a×a + a×b + b×a + b×b

= a^2 + ab + ab + b^2

= a^2 + 2ab + b^2

Hence proved....

for eg.

(3+5)^2 =????

here a=3, b=5

(3+5)^2=3^2 + 2×3×5 + 5^2

8^2 = 9 + 30 + 25

64 = 9 + 55

64 = 64

LHS = RHS

H.P..........

Hope it helps you....