Question

verify the associative law of multiplication -3/11,-7/4 and -1/2
please give the answer fast
its very urgent
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Answer 1

Solution:

Associative law of multiplication states that:

(a × b) × c = a × (b × c)

Here:

• a = -3/11
• b = -7/4
• c = -1/2

a × b

$= \dfrac{ - 3}{11} \times \dfrac{ - 7}{4}$

$= \dfrac{21}{44}$

Now for b × c

$= \dfrac{ - 7}{4} \times \dfrac{ - 1}{2}$

$= \dfrac{7}{8}$

We need to verify whether

(a × b) × c = a × (b × c)

So,

$\to \: \dfrac{21}{44} \times \dfrac{ - 1}{2} = \dfrac{ - 3}{11} \times \dfrac{7}{8}$

$\implies \dfrac{ - 21}{88} = \dfrac{ - 21}{88}$

★ HENCE VERIFIED ★

KNOW MORE:

• There is another important property known as Commutative law which states that:

(a × b) = (b × a)

Answer 2

$\bigstar \: \underline{ \sf \: Associative \: law \: of \: multiplication} :$

(a × b) × c = a × (b × c)

Let's Do this :

a = -3/11

b = -7/4

c = -1/2

a × b

$\: \: \: \: \: \sf : \implies\dfrac{ - 3}{11} \times \dfrac{ - 7}{4}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf: \implies\dfrac{21}{44}$

Now b × c :

$\: \: \: \: \: \sf:\implies \dfrac{ - 7}{4} \times \dfrac{ - 1}{2}$

$\: \: \: \: \: \: \sf:\implies \dfrac{7}{8}$

Now verify the whether :

(a × b) × c = a × (b × c)

So,

$\: \: \: \: \: \: : \implies \sf \dfrac{21}{44} \times \dfrac{ - 1}{2} = \dfrac{ - 3}{11} \times \dfrac{7}{8}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf: \implies \dfrac{ - 21}{88} = \dfrac{ - 21}{88}$

Hence, L.H.S = R.H.S