verify the BPT for a triangle,using parallel line board and triangle cut outs
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Verifying the BPT for a triangle, using parallel line board and triangle cut outs.
BPT Definition:
BPT- Basic Proportionality Theorem says, if a triangle is divided by a parallel line, that intersecting two sides of the triangle, the other two side should divide at a same ratio.
Constrionuct:
Consider a triangle ΔABC.
Draw a parallel line DE.
DE should be parallel to BC- DE∥ BC.
Now Join BE
Join CD
Now draw EQ ⊥ AB
Draw DP ⊥ AC
To Prove: AD/DB = AE/EC, so, we can prove DE divides, AB and AC in a same ration.
Follow the procedure to prove the above:
- Calculate the area of the triangle ADE by keeping the AD as base and EQ as the altitude. And then, calculate the area of the triangle DBE using DB as base and EQ as altitude.
- Find the ratio of the two areas of the triangles ADE and DBE, you'll get AD/DB
- Now, repeat the process for triangles ADE and EDC and find the ratio of their areas, to get AE/EC.
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sorry can anyone explain me
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