verify the distributive property a x (b+c)= (axb)+(axc) for the rational numbers a= 2 1 b= 3 2 c= 6 5
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Step-by-step explanation:
LHS, first sum the integers in brackets b+c = -9+8 =-1
Then multiply the above sum by a=-10, -10*-1 = 10 = LHS
Now the RHS, first the muplication in brackets (-10*-9)+(-10*8) = 90–80 = 10 = LHS
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