Verify the distributive property a x (b+c) = (axb) + (axc) where a= , b= , c =
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Answer:
Below.
Step-by-step explanation:
Let a = 2, b = 3 and c = 4. Then
a( x b + c) = 2(3 + 4) = 2x7 = 14.
(a x b) + (a x c) = 2x3 + 2x4 = 6+8 = 14.
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Answer:
a×[b+C) = a× b + a× C
a=1/2,b = 2)3 C = 1/3 a× ( b+C= a×b + a× C
1/2 × [ 2/3+[2/3]
=1/2×2/3)+
(1/2×[-1/3]
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