Question

Verify the each of the following using the laws of exponents 1/9(3)^3x=3^3x-2

Answer 1

Answer:

$point) \: \: \: {x}^{ - a} = \frac{1}{ {x}^{a} } \: \: \\ point) \: \: {x}^{p} \times {x}^{q} \: = {x}^{p + q} \: \\ \frac{1}{9} \times {3}^{3x} = {3}^{3x} \times {3}^{ - 2} \\ \frac{1}{9} \times {3}^{3x} = {3}^{3x} \times \frac{1}{{3}^{2}} \\ \frac{1}{9} \times {3}^{3x} = \frac{1}{9} \times {3}^{3x}$

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

point)x

−a

=

x

a

1

point)x

p

×x

q

=x

p+q

9

1

×3

3x

=3

3x

×3

−2

9

1

×3

3x

=3

3x

×

3

2

1

9

1

×3

3x

=

9

1

×3

3x