Question

Verify the expression n! = 0(nⁿ).

Answer 1

In this Case, In R.H.S, if you will put n=any interger there result will become 0 as 0 is in multiplication factor outside the bracket...

So, R.H.S=0 (Fixed value)

But in L.H.S, if you will put least possible number 0 (Not -ve in ! one) then it becomes 1 atleast........

So, L.H.S.=1 (Least possible value)

   So, R.H.S. can never be equal to L.H.S. in that case..........