Verify the following 22×[(-2)+3]=22×(-2)+22×3
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Answered by
0
Answer:
Let zeros of cubic polynomial are α,β and γ. Then
α+β+γ=0
αβ+βγ+αγ=−7
αβγ=−6
Now, the required polynomial is
x
3
−(α+β+γ)x
2
+(αβ+βγ+αγ)x−(αβγ)
Therefore, the required polynomial is x
3
−(0)x
2
+(−7)x−(−6) i.e x
3
−7x+6
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