Question

verify the following 28×[10+(-7)]=(28×10)+[28×(-7)]​

Answer 1

Step-by-step explanation:

First take a^2= 28 - 10*3^(1/2)

=> 5^2 + (- 3^1/2) ^2+ 2 . 5.(-3^1/2) {{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}

=> (5 - 3^(1/2)) ^2

That gives a = 5 - 3^1/2

Now let b^2 = 1/(7 + 4.3^1/2)

Multiply by 7 - 4.3^1/2 on both numerator and denominator

gives, b^2 = 7 - 4.3^1/2

=> (2)^2 + (-3^1/2)^2 + 2.(2).(-3^1/2)

{{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}So this gives

b = 2 - 3^1/2

You asked the value of a- b = 5 - 2 = 3

This seems to be the most appropriate answer.

hope it will help you

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