Verify the following
{(7)^-1]^2 = 49
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{(7)^-1}^2=49
(If we multiply 7 by -1 as given in question
It will be -7)
(-7)^2
(here power of 7 is now 2 , so we will multiply 7 two times)
-7×-7 = 49
LHS=RHS
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