Question

verify the following a) 18×(9+(-3)= (18×9)+(18×(-3)

Answer 1

We have LHS and RHS

Here you should apply BODMAS RULE (B-bracket,O-of, D-division,M-multiplication,A-addition,S-subtraction)

CONSIDER LHS:
First you have to remove the bracket,acc to bodmas

18×(9+(-3)
=18×(9-3)
=18×6=108

NOW CONSIDER RHS:
(18×9)+(18×(-3))
(18×9)+(-54)
162-54=108

Hence we have proved that LHS=RHS

Answer 2

To verify this we have to take L.H.S and R.H.S.

W have to solve both side by appling BODMAS rule (i.e B-bracket,O-of, D-division,M-multiplication,A-addition,S-subtraction)

NOW
L.H.S = 18×(9+(-3)
          =18×(9-3)
          =18×6=108

R.H.S=(18×9)+(18×(-3))
          =(18×9)+(-54)
          =162-54
          =108

⇒L.H.S = R.H.S

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ROYALJATT