Verify the following: (a^2-b^2)(a^2+b^2)+(b^2-c^2)(b^2+c^2)+(c^2-a^2)(c^2+a^2)=0
Use factorisation method
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Answer:
We know that the factor theorem states that if the polynomial p(x) is divided by cx−d and the remainder, given by p(
c
d
), is equal to zero, then cx−d is a factor of p(x).
Consider the given expression a(b
2
−c
2
)+b(c
2
−a
2
)+c(a
2
−b
2
) and solve it as follows:
a(b
2
−c
2
)+b(c
2
−a
2
)+c(a
2
−b
2
)
=ab
2
−ac
2
+bc
2
−ba
2
+c(a−b)(a+b)(∵(x+y)(x−y)=x
2
−y
2
)
=ab
2
−ba
2
−ac
2
+bc
2
+c(a−b)(a+b)
=ab(b−a)−(a−b)c
2
+c(a−b)(a+b)
=−ab(a−b)−(a−b)c
2
+c(a−b)(a+b)
=(a−b)(−ab−c
2
+c(a+b))
=(a−b)(c(a+b)−ab−c
2
)
Hence, by factor theorem (a−b) is a factor of a(b
2
−c
2
)+b(c
2
−a
2
)+c(a
2
−b
2
).
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