verify the following are roots of the polynomial x²-5x+6=0; x=2,3
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When x = 2, the value of the polynomial x²-5x+6 is
2² - 5×2 + 6 = 4 - 10 + 6 = 10 - 10 = 0
Since value of polynomial at x=2 is 0, 2 is a root of the polynomial.
When x = 3, the value of the polynomial x²-5x+6 is
3² - 5×3 + 6 = 9 - 15 + 6 = 15 -15 = 0
Since value of polynomial at x=3 is 0, 3 is a root of the polynomial.
2² - 5×2 + 6 = 4 - 10 + 6 = 10 - 10 = 0
Since value of polynomial at x=2 is 0, 2 is a root of the polynomial.
When x = 3, the value of the polynomial x²-5x+6 is
3² - 5×3 + 6 = 9 - 15 + 6 = 15 -15 = 0
Since value of polynomial at x=3 is 0, 3 is a root of the polynomial.
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