Question

Verify the following are zeroes of the polynomial,indicated against them.

p(x)=x^2-1,X=1,-1​

Answer 1

Step-by-step explanation:

${\ sf{ \underline{ \red{ \underline{ \red{Given}}}} : -}}$

$\displaystyle \sf \bigstar \: \: \: \: \: \small{ \rm{ \pink{ p(x) \: = \: {x}^{2} - 1}}} \\ \\ \displaystyle \sf \bigstar \: \: \: \: \: \small{ \rm{ \pink{ (x) = \: 1 \: \: \: - 1}}} \: \:$

${ \sf{ \underline{ \red{ \underline{ \red{Solution}}}} : - }}$

$\displaystyle \sf \bigstar \: \: \: \: \small{ \sf{ \pink{x = 1}}} \\ \\ \displaystyle \tt : \implies \: {x}^{2} - 1 \: \: \: \: \: \: \: \\ \\ \displaystyle \tt : \implies \: 1 - 1 = 0 \\ \\ \\ \displaystyle \sf \bigstar \: \: \: \: \small{ \sf{ \orange{x = - 1}}} \\ \\ \displaystyle \tt : \implies \: {x}^{2} - 1 \: \: \: \: \: \: \ \\ \\ \displaystyle \tt : \implies \: 1 - 1 = 0$