Verify the following Boolean Expression using truth table. X.Y.Z + X.Y’.Z + X.Y.Z = X.(Y + Z)
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Explanation:
X Y Z Y+Z X+(Y+Z) (X+Y) (X+Y)+Z
0 0 0 0 0 0 0
0 0 1 1 1 0 1
0 1 0 1 1 1 1
0 1 1 1 1 1 1
1 0 0 0 1 1 1
1 0 1 1 1 1 1
1 1 0 1 1 1 1
1 1 1 1 1 1 1
As the values of columns X+(Y+Z) and (X+Y)+Z are identical, hence the expression is proved.
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