Question

verify the following.
C. (-32) x [(-2) + (-1)] = [(-32) (-2)] + [(-32)x (-1)]
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Answer 1

Answer:

(96)=(96)

Step-by-step explanation:

(-32)×[(-2)+(-1)]=[(-32)(-2)]+[(-32)×(-1)]

(-32)×(-3)=(64)+(32)

(96)=(96)

96=96

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Answer 2

$\bf Let's \: solve\: your\: equation\: step\:-by-\:step.$

$\sf (−32x)(−2−1)=(−32)(−2)+(−32x)(−1)$

$\rm Step\: 1: Simplify\: both\: sides\: of\: the\: equation.$

$\sf (−32x)(−2−1)=(−32)(−2)+(−32x)(−1)$

$\sf 96x=64+32x$

$\sf 96\:x=32\:x+64$

$\rm Step \:2:\: Subtract\: 32x\: from \:both\: sides.$

$\sf 96x−32x=32x+64−32x$

$\sf 64x=64$

$\rm \:Step\: 3: \:Divide\: both\: sides\: by\: 64.$

$64x \div 64 \: =6464$

x=1

$\sf Answer:$

$\sf x=1$