Question

verify the following Q. (-8+1/4)+(-3/17)=8+[1/4+-(3/17)]

Answer 1

Check sum they are not equal

Answer 2

Question:

• To verify : $\sf -8 +\dfrac{1}{4}+\left(-\dfrac{3}{17}\right) =-8+\left[\dfrac{1}{4}+\left(-\dfrac{3}{17}\right)\right]$

Solution:

$\large\underbrace{\sf Solving\;\red{L.H.S}} :$

$\longmapsto \sf -8 +\dfrac{1}{4}+\left(-\dfrac{3}{17}\right) \\\\\dashrightarrow \dfrac{-8(4)+1(1)}{4}+\left(-\dfrac{3}{17}\right) \\\\\dashrightarrow \dfrac{-32+1}{4} -\dfrac{3}{17}\\\\\dashrightarrow \dfrac{-31}{4} -\dfrac{3}{17}\\\\\dashrightarrow \dfrac{-31(17)-3(4)}{68} \\\\\dashrightarrow\dfrac{-527-12}{68}\\\\\dashrightarrow\dfrac{-539}{68}$

$\large\underbrace{\sf Solving\;\red{R.H.S}} :$

$\longmapsto\sf -8+\left[\dfrac{1}{4}+\left(-\dfrac{3}{17}\right)\right]\\\\\dashrightarrow -8+\left[\dfrac{1}{4}-\dfrac{3}{17}\right]\\\\\dashrightarrow -8+\left[\dfrac{1(17)-3(4)}{68}\right]\\\\\dashrightarrow -8+\dfrac{17-12}{68}\\\\\dashrightarrow-8+\dfrac{5}{68}\\\\\dashrightarrow \dfrac{-544+5}{68}\\\\\dashrightarrow\dfrac{-539}{68}$

L.H.S = R.H.S

$\large\underline{\mathfrak{\green{Hence\;verified\displaystyle!\,}}}$