Question

Verify the following system of linear equations is diagon
2x+y+z=4, x+4y+8z=13 and x+3y+z=5​

Answer 1

Answer:

ANSWER

Consider

3x+4y+5z=6 ...(i)

2x+3y+4z=5 ...(ii)

x+2y+3z=4 ...(iii)

Therefore,

∣

∣

∣

∣

∣

∣

∣

∣

3

2

1

4

3

2

5

4

3

∣

∣

∣

∣

∣

∣

∣

∣

=3(9−8)−4(6−4)+5(4−3)

=3+5−(4×2)

=8−8

=0