verify the following zeroes of the polynomial indicate against them
p(x)=x²-1 where x=1,-1
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1
Step-by-step explanation:
er thee diff yours sorry
Answered by
0
Answer:
p(x)=x
2
−1:
Put x=1, we get,
p(x)=p(1)=(1)
2
−1=1−1=0.
So, x=1 is the zero of the given polynomial p(x).
Now put x=−1, we get,
p(x)p(−1)=(−1)
2
−1=1−1=0.
So, x=−1 is the zero of the given polynomial p(x).
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