Math, asked by deonathsaipainkra, 14 days ago

verify the given statement by solving both the side
(a) (-2) power 4 ×(-2) power 2 = (-2) power 8÷(-2) power 2
(b) (-3)power 2 × (-3) power -6= 1 by (3
square) power 2
(c) (-7) power 32 ÷ (-7) power 32 = 1

Answers

Answered by bamanabhargav9
0

Answer:

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Answered by RvChaudharY50
2

Solution :-

a) (-2) power 4 ×(-2) power 2 = (-2) power 8÷(-2) power 2

→ (-2)⁴ * (-2)² = (-2)⁸ ÷ (-2)²

using a^m * a^n = a^(m + n) in LHS and a^m ÷ a^n = a^(m - n) in RHS,

→ (-2)^(4 + 2) = (-2)^(8 - 2)

→ (-2)⁶ = (-2)⁶

→ 64 = 64 (Proved)

b) (-3)power 2 × (-3) power -6= 1 by (3

square) power 2

→ (-3)² * (-3)^(-6) = 1/(3²)²

using a^m * a^n = a^(m + n) in LHS ,

→ (-3)^(2 - 6) = 1/3⁴

using 1/a^m = a^(-m) in LHS,

→ 1/(-3)⁴ = 1/3⁴

→ 1/81 = 1/81 (Proved)

c) (-7) power 32 ÷ (-7) power 32 = 1

→ (-7)³² ÷ (-7)³² = 1

using a ÷ a = 1

→ 1 = 1 (proved)

Learn more :-

(3) निम्न के स्थानीय मान लिखिये-

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