verify the given statement by solving both the side
(a) (-2) power 4 ×(-2) power 2 = (-2) power 8÷(-2) power 2
(b) (-3)power 2 × (-3) power -6= 1 by (3
square) power 2
(c) (-7) power 32 ÷ (-7) power 32 = 1
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Solution :-
a) (-2) power 4 ×(-2) power 2 = (-2) power 8÷(-2) power 2
→ (-2)⁴ * (-2)² = (-2)⁸ ÷ (-2)²
using a^m * a^n = a^(m + n) in LHS and a^m ÷ a^n = a^(m - n) in RHS,
→ (-2)^(4 + 2) = (-2)^(8 - 2)
→ (-2)⁶ = (-2)⁶
→ 64 = 64 (Proved)
b) (-3)power 2 × (-3) power -6= 1 by (3
square) power 2
→ (-3)² * (-3)^(-6) = 1/(3²)²
using a^m * a^n = a^(m + n) in LHS ,
→ (-3)^(2 - 6) = 1/3⁴
using 1/a^m = a^(-m) in LHS,
→ 1/(-3)⁴ = 1/3⁴
→ 1/81 = 1/81 (Proved)
c) (-7) power 32 ÷ (-7) power 32 = 1
→ (-7)³² ÷ (-7)³² = 1
using a ÷ a = 1
→ 1 = 1 (proved)
Learn more :-
(3) निम्न के स्थानीय मान लिखिये-
(अ)43.24
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(द) 178.34
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