Question

Verify the identity (a+b)^2= a^2+2ab+b^2 geometrically by taking a=3 and b=2

Answer 1

$\huge\mathbb{SOLUTION}}$

$\bold{(a+b)^2=a^2+2ab+b^2}}$

Draw a square with the side a+b,I,e 3+2

L.H.S area of whole square

$\large\bold{=(3+2)^2=5^2=25}$

R.H.S. = area of square with 3units + area of square with side 2 units + area of rectangle with sides 3,2units+area of rectangle with sides 2,3 units

$\large\bold{=3^2+2^2+3*2+3*2}$

$\large\bold{=9+4+6+6=25}$

$\large\bold{l.h.s=r.h.s}$

Therefore hence the identity is verified

Answer 2

$\mathtt{hello \: your \: answer \: is....} \\ \\ \mathfrak{ {a + b}^{2} = {a}^{2} + {b}^{2} + 2ab} \\ \mathfrak{{(a + b)}^{2} = (a + b)(a + b)} \\ \mathfrak{= a(a + b) + b(a + b) }\\ = {a}^{2} + ab + ab + {b}^{2} \\ = \fbox\mathfrak \blue {{a}^{2} + {b}^{2} + 2ab} \\ \mathsf{ \because \: hence \: proved} \\ \\ hopei \\ \: it \\ \: \: helps \\ you \\ plz \\ make \\ me \\ brainliest$