Question

verify the identity (a-b)²=a²-2ab+b² geometrically by taking a=3 , b=2

Answer 1

LHS = (a-b)² = (3-2)² = 1² = 1

RHS = a²-2ab+b² = 3²-2(3)(2)+2²

= 9-12+4 = 1
since LHS = RHS Verified...

Answer 2

Answer: The answer will be one and L.H.S=R.H.S will be proved.

Step-by-step explanation:

So here a=3 and b=2.

L.H.S= (a-b)^2 = (3-2)^2= (1)^2 = 1

R.H.S= a²-2ab+b² = (3)² - (2*3*2) + (2)² = 9-12+4 = -3+4 = 1

so both the side, result is 1.

Hence L.H.S = R.H S it is proved.

Hope it answers your question. All the best!