Question

Verify the identity (a+b)²=a²+2ab+b²when a=3andb=4

Answer 1

✏ Answer :

$(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2} \\ (3 + 4) {}^{2} = (3) {}^{2} + 2(3)(4) + (4) {}^{2} \\ (7) {}^{2} = 9 + 24 + 16 \\ \\ 49 = 49$

✔ Verified

Answer 2

Answer:

Solution :-

➡ Given a = 3 and b = 4...then

➡To verify :-

$(a + b {)}^{2} = {a}^{2} + 2ab + {b}^{2}$

So

$(3 + 4 {)}^{2} = (3 {)}^{2} + 2 \times 3 \times 4 + {4}^{2} \\ \\ (7 {)}^{2} = 9 + 24 + 16 \\ \\ 49 = 49$

Hence verified ! ❤

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