Question

verify the identity a-b²=a²-2ab+b² geometrically by taking (i) a=3 units ,b=1 unit (ii)a=5 units,b=2 units​

Answer 1

Answer:

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Answer 2

Answer:

$we \: have \: {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ taking \: (i) \\ a = 3 \: units \\ b = 1 \: unit \\ putting \: values \: in \: equation \\ {(3 - 1)}^{2} = {(3)}^{2} - 2(3)(1) + {(1)}^{2} \\ {(2)}^{2} = 9 - 6 + 1 \\ 4 = 3 + 1 \\ 4 = 4 \\ l.h.s = r.h.s \\ \\ taking \: (ii) \\ a = 5\: units \\ b = 2\: units \\ {(5 - 2)}^{2} = {(5)}^{2} - 2(5)(2) + {(2)}^{2} \\ {(3)}^{2} = 25 - 20 + 4 \\ 9 = 5 + 4 \\ 9 = 9 \\ l.h.s = r.h.s \\ \\ so \: in \: both \: cases \: l.h.s = r.h.s \\ hence \: verified \\ \\ \\ hope \: it \: helps............. \\ plz \: mark \: as \: brainliest..............$